10n^2-95n-50=0

Solution for 10n^2-95n-50=0 equation:

10n^2-95n-50=0

a = 10; b = -95; c = -50;
Δ = b2-4ac
Δ = -952-4·10·(-50)
Δ = 11025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11025}=105$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-95)-105}{2*10}=\frac{-10}{20}
=-1/2
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-95)+105}{2*10}=\frac{200}{20}
=10
$